8h^2+60h+52=0

Solution for 8h^2+60h+52=0 equation:

8h^2+60h+52=0

a = 8; b = 60; c = +52;
Δ = b2-4ac
Δ = 602-4·8·52
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-44}{2*8}=\frac{-104}{16}
=-6+1/2
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+44}{2*8}=\frac{-16}{16}
=-1
$